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developersSave
2 years agoHelpful | Level 6
Move files and Folders
Hi everyone, I've a question: I need to move files and folders using dropbox API in my Java project. Do you have some code examples? I can't find them online and I don't know if it's possibile do ...
- 2 years ago
Hi Здравко ,
I solved everything in this way (all Paths are made with a DropBox id):
public static String moveFile(SuiteConfiguration suiteConfiguration,
String fromPath,String toPath) throws RelocationErrorException, DbxException {
DbxClientV2 dropboxClient = getV2Client(suiteConfiguration);
"id:TMSaeghsn0AAAAAAAACV2w/ios.png").withAllowOwnershipTransfer(true).withAllowSharedFolder(true).withAutorename(true);
RelocationResult result = dropboxClient.files().moveV2(fromPath, toPath);
return result.getMetadata().getPathDisplay();
}
public static void moveFolder(SuiteConfiguration suiteConfiguration,
String fromPath,String toPath) throws RelocationErrorException, DbxException, InterruptedException {
DbxClientV2 dropboxClient = getV2Client(suiteConfiguration);
MoveV2Builder withAllowSharedFolder = dropboxClient.files().moveV2Builder(fromPath,toPath).withAllowOwnershipTransfer(true).withAllowSharedFolder(true).withAutorename(false);
RelocationResult result = withAllowSharedFolder.start();
}
Thank you for your help
Здравко
2 years agoLegendary | Level 20
Hi developersSave,
You can use moveV2 method to move/rename a file/folder. For different examples showing simple applications (hello world style), take a look here.
Hope this helps.
- developersSave2 years agoHelpful | Level 6
Hi Здравко
That's my code! I'm trying to get my new folder path from it dropbox id using getFolderPath() method, but it doesn't work.
After that, I use moveFile() method.public static String getFolderPath(SuiteConfiguration suiteConfiguration, String id) throws DbxException {
DbxClientV2 dropboxClient = getV2Move(suiteConfiguration);
String folderPath = "";
try {
Metadata metadata = dropboxClient.files().getMetadata(id);
if (metadata instanceof FolderMetadata) {
folderPath = ((FolderMetadata) metadata).getPathDisplay();
}
} catch (DbxException e) {
e.printStackTrace();
}
return folderPath;
}
public static FileMetadata moveFile(SuiteConfiguration suiteConfiguration,
String fromPath,String toPath) throws RelocationErrorException, DbxException {
DbxClientV2 dropboxClient = getV2Move(suiteConfiguration);
RelocationResult result = dropboxClient.files().moveV2(fromPath, toPath);
return (FileMetadata) result.getMetadata();
}
- Здравко2 years agoLegendary | Level 20
developersSave wrote:... I'm trying to get my new folder path from it dropbox id using getFolderPath() method, ...
developersSave, You don't need to get existing file/folder path from id. The id may be used on path's place instead. So, your 'getFolderPath' is meaningless here. Even more - what about files:
developersSave wrote:...
try {
Metadata metadata = dropboxClient.files().getMetadata(id);
if (metadata instanceof FolderMetadata) {
folderPath = ((FolderMetadata) metadata).getPathDisplay();
}
} catch (DbxException e) {
e.printStackTrace();
}
...
'FolderMetadata' Ok, but what about 'FileMetadata'? A valid object will leads to empty file name; of course incorrect when you pass it to 'moveFile'!
By the way, what kind of error your're receiving? There has to be a clear enough description. What do you exactly mean with "it doesn't work"? 🧐
- developersSave2 years agoHelpful | Level 6
Good morning Здравко,
By applying the firt method I would like to retrieve both the "from" path (the origin folder) and the "to" path (the destination folder), but I'm getting the following error: com.dropbox.core.v2.files.GetMetadataErrorException: Exception in 2/files/get_metadata: {".tag":"path","path":"not_found"}
Once I have retrieved both paths, by applying the second method I'd like to carry out the move.
Could you suggest me a way to do this?
Also, what do you mean exactly when you say "meaningless"? Could you explain a little bit better?
It's the first time I use Dropbox to do this and naybe there is something I'm doing wrong without knowing.
Thank you!
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