Get the URL path from a link bookmark .url file

Thank you, Greg.  This gave me what I needed!  

I was not familiar with what to with the raw binary data returned from Dropbox.  After combining some answers from StackOverflow this is what I came up with which is working for me in my Angular 1 application.  I hope this code will help someone else who might be looking for this!

            function downloadFile(filePath) {
                if (!filePath) {
                    console.error('Cannot download file because no file was specified.');
                    return;
                }
                return $q(function(fulfill, reject) {
                    $http({
                        url: `${dropboxContent}/2/files/download`,
                        method: 'POST',
                        headers: {
                            'Authorization': 'Bearer {{access-token-goes-here}}',
                            'Dropbox-API-Arg': `{"path": "${filePath}"}`
                        },
                        responseType: 'blob'
                    }).then(
                        results => {
                            // data received from dropbox is binary data saved as a blob
                            // The FileReader object lets web applications asynchronously read the contents of files
                            // https://developer.mozilla.org/en-US/docs/Web/API/FileReader
                            var fileReader = new FileReader();
                             // function will run after successfully reading the file
                            fileReader.onload = function() {
                                var string = this.result; // store the file contents
                                string = encodeURI(string); // get rid of the paragraph return characters
                                var endPosition = string.indexOf('%0D%0A', 32); // find the end of the URL, startPosition is 32
                                var actualURL = string.substring(32, endPosition); // grab only the characters between start and end positions
                                fulfill(actualURL);
                            };
                            fileReader.readAsText(results.data);                           
                        },
                        error => reject(error));
                });
            }

The tricky part is that you have to be able to 'read' the blob that is returned, and then extract out just the 'URL'.